Question

1. Solve the system using substitution (1 point)

x + y = 8
y = 3x

(A). (4, 12)
(B). (2, 6)
(C). (1/2, 3/2)
(D). (-4, -12)

2. Solve the system using substitution (1 point)

2x + 2y = 38
y = x + 3

(A). (8, 11)
(B). (4, 7)
(C). (35/4, 47/4)
(D). (-4, -7)

3. Solve the system using substitution (1 point)

y = 8 - x
7 = 2 - y

(A). (5, 13)
(B). (13, -5)
(C). (3, 5)
(D). (21, -13)

4. Solve the system using substitution (1 point)

3x + 2y = 23
1/2x - 4 = y

(A). (9, -2)
(B). (27/4, -5/8)
(C). (31/4, -1/8)
(D). (3/2, -13/4)

5. Solve the system using substitution (1 point)

y - 2x = 3
3x - 2y = 5

(A). (-1/2, 2)
(B). (2, 7)
(C). (-8, -13)
(D). (-11, -19)

Unit 7 Lesson 2, Solving Systems Using Substitution. If you completed this Algebra lesson yet please give me the rest of the answers!! Thanks!! :)

Answer 1

I'll do the first two so that you can try and practice them on your own.

1.

y = 3x, let's input that into the other equation.

x + 3x = 8
4x = 8
Divide both sides by 4.
x = 2

y = 3(2)
y = 6

(2, 6)

2.

y = x + 3, let's input that into the other equation.

2x + 2(x + 3) = 38
2x + 2x + 6 = 38
Subtract 6 from both sides.
4x = 32
Divide both sides by 4.
x = 8

y = 8 + 3
y = 11

(8, 11)

Good luck!

Answer 2

Answer:

Solving systems  using substitution practice  (I just did this, so I know they are all right) 1-10

Step-by-step explanation:

1. B

2. A

3. B

4. C

5. D

6. A

7. A

8. B

9. C

10. A