Question

Huntington\'s disease is an inherited autosomal dominant disorder that can affect both men and women. imagine a couple has had seven children, and later in life, the husband develops huntington\'s disease. he is tested and it is discovered he is heterozygous for the disease allele, hh. the wife is also genetically tested for the huntington\'s disease allele, and her test results show she is unaffected, hh. what is the percent probability that the first child of this couple will have huntington\'s disease?

Answer 1

25 % chances are there to catch disease by the first child

Answer 2

Answer: The percent probability is 50% of having Huntington's disease.

Explanation: Beingan autosomal dominant disorder means that individuals who have the allele H is carrier and the disease will manifest.

The husband develops it, which means he has the allele, but the test says he is heterozygous, so his genotype is Hh.

The wife's test shows she is not a carrier or has the disease, so her genotype is hh.

Using a Punnett Square, which is a diagram that shows the offspring's genotype and probabilities, we have:

      H     h

h   Hh    hh

h   Hh    hh

It shows that the child of this couple has a probability of 50% of having the disease and have the genotype Hh.