What volume of a 0.160 m solution of koh must be added to 450.0 ml of the acidic solution to completely neutralize all of the acid?

Respuesta :

An  acidic  solution  is 0.1M  in  HCl  and  0.2  H2so4. volume  is  equal  to  no  of  moles  divided  by  molarity.  
number  of  moles  of  HCl is  450ml x 0.1  divided  by 1000  which is equal  to 0.045 moles
volume  of  HCl   is  therefore  0.45  divided  by  0.16  which  is   2.81  litres

Number  of  moles  of  H2so4  is  450ml x 0.2  divided  by  1000  which  is  equal  to  0.09  moles
volume  of  H2SO4  IS  0.09 divided  by  0.16  which  is  equal  to  0.56 litres

Volume KOH to completely neutralize all of the acid = 1406.25 ml

Further explanation

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint / equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.

An acid-base titration there will be a change in the pH of the solution.

From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution

Acid-base titration formula

Ma Va. na = Mb. Vb. nb

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence

Since the concentration of the acid solution is unknown, we suppose that the solution is:

0.10M in HCl and 0.20 M in H2SO4

1. HCl

Ma Va. na = Mb. Vb. nb

a = HCl, b = KOH

na = valence HCl = 1 (yields 1 H + ion in solution)

nb = valence KOH = 1 (yields 1 OH- ion in solution)

0.10. 450 1 = 0.16. Vb. 1

Vb = 281.25 ml

2. H2SO4

Ma Va. na = Mb. Vb. nb

a = H2SO4, b = KOH

na = valence H2SO4 = 2 (yields 2 H + ions in solution)

nb = valence KOH = 1 (yields 1 OH- ion in solution)

0.20 450 2 = 0.16. Vb. 1

Vb = 1125 ml

Vb tot = 281.25 + 1125 = 1406.25 ml

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