Respuesta :
An acidic solution is 0.1M in HCl and 0.2 H2so4. volume is equal to no of moles divided by molarity.
number of moles of HCl is 450ml x 0.1 divided by 1000 which is equal to 0.045 moles
volume of HCl is therefore 0.45 divided by 0.16 which is 2.81 litres
Number of moles of H2so4 is 450ml x 0.2 divided by 1000 which is equal to 0.09 moles
volume of H2SO4 IS 0.09 divided by 0.16 which is equal to 0.56 litres
number of moles of HCl is 450ml x 0.1 divided by 1000 which is equal to 0.045 moles
volume of HCl is therefore 0.45 divided by 0.16 which is 2.81 litres
Number of moles of H2so4 is 450ml x 0.2 divided by 1000 which is equal to 0.09 moles
volume of H2SO4 IS 0.09 divided by 0.16 which is equal to 0.56 litres
Volume KOH to completely neutralize all of the acid = 1406.25 ml
Further explanation
Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint / equivalence point of the reaction can use indicators according to the appropriate pH range
Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.
An acid-base titration there will be a change in the pH of the solution.
From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution
Acid-base titration formula
Ma Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence
Since the concentration of the acid solution is unknown, we suppose that the solution is:
0.10M in HCl and 0.20 M in H2SO4
1. HCl
Ma Va. na = Mb. Vb. nb
a = HCl, b = KOH
na = valence HCl = 1 (yields 1 H + ion in solution)
nb = valence KOH = 1 (yields 1 OH- ion in solution)
0.10. 450 1 = 0.16. Vb. 1
Vb = 281.25 ml
2. H2SO4
Ma Va. na = Mb. Vb. nb
a = H2SO4, b = KOH
na = valence H2SO4 = 2 (yields 2 H + ions in solution)
nb = valence KOH = 1 (yields 1 OH- ion in solution)
0.20 450 2 = 0.16. Vb. 1
Vb = 1125 ml
Vb tot = 281.25 + 1125 = 1406.25 ml
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