Four Part question! Please answer! WILL MEDAL

PART ONE:The main show tank has a radius of 60 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of the pool is flat. (Imagine cutting a sphere in half vertically and then cutting it in half horizontally.) What is the volume of the quarter-sphere shaped tank? Round your answer to the nearest whole number. You must explain your answer using words, and you must show all work and calculations to receive credit.

PART TWO: The holding tanks are congruent. Each is in the shape of a cylinder that has been cut in half vertically. The bottom of each tank is a curved surface and the top of the pool is a flat surface. What is the volume of both tanks if the radius of tank #1 is 30 feet and the height of tank #2 is 110 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.

PART 3: The company is building a scale model of the theater’s main sh

Respuesta :

Part 3:

The volume of a sphere is given by:

[tex]V= \frac{4}{3} \pi r^3[/tex]

Given that the main show tank has a radius of 60 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of the pool is flat.

The volume of
the quarter-sphere shaped tank is given by:

[tex]V= \frac{1}{4} \cdot \frac{4}{3} \pi (60)^2=1200\pi\approx3770\, cubic\, ft.[/tex]



Part 2:

The volume of a cylinder is given by:

[tex]V=\pi r^2h[/tex]

Given that
the holding tanks are in the shape of a cylinder that has been cut in half vertically.

The volume of the tanks if tank #1 have a radius of 30 feet and the height of tank #2 is 110 feet.

Since both tanks are congruent, then the radius and the height of both matches are equal.

Therefore the volume of the half-tanks is given by:

[tex]V= \frac{1}{2} \pi(30)^2\times110=49,500\pi\approx155,509\, cubic\, ft[/tex]



Part 3:

The volume of a the tank is given by:

[tex]V=LWH[/tex]

Given that the dimensions of the mock-uk is 1/8 the original dimensions, then the volume of the mock up is given by:

[tex]Volume= \frac{L}{8} \times \frac{W}{8} \times \frac{H}{8} = \frac{1}{512} LWH[/tex]

Therefore, the volume of the mock-up is 1/512 the volume of the original tank.
ACCESS MORE