The generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 were found to be [a] = 0.100 m, [c] = 0.0320 m, and [ac5] = 0.100 m. determine the formation constant, kf, of ac5.
AB (s)plus 5C(aq) <-> AC5 (aq)plus B(aq) ,KF is equal to (AC5)/(A) (C)^5 which is 0.100/ (0.001m) (0.032)^5 which is equal to 2.9x10^7
AB sokubility in 1.000 solution of C is 0.121M. find the ksp of AB
from ICE table the change is equivalent to solubility which is 0.121m. therefore k for (AC) is 0.121and since ratio of AC to B is 1:1 that of (B)is also 0.121 (C) is 1.00- 5(0.121) which is 0.605 k is equal to (0.121) / (0.0121)(0.605)^5 which is 1.5237 1.5237 is then divided by 2.9x10^7 which is 5.3x10^-8
