The length of the field is 48 yard while the width of the field is 16 yards.
My Work/Reasoning:
Say that the width is "x" yards. [tex]x[/tex]
The length of the field is three times longer than the width. [tex]3x[/tex]
The perimeter of the rectangle is 128 yards. [tex]128[/tex]
To get the perimeter of a rectangle you multiply the sum of the length and the width by two. [tex]2(x+3x)=128[/tex]
Then you follow order of operations and add x and 3x. [tex]2*4x=128[/tex]
Then you multiply. [tex]8x=128[/tex]
After that, you divide 8 on both sides to get the width (total) in yards. [tex]x=32[/tex]
Then you divide that to get the width. [tex]32/2=16[/tex]
Finally, to get the length of the field, you multiply the width of the field by three to get its length. [tex]16*3=48[/tex]
