Question

The function f(x)=5(x−1) is shown on the coordinate plane. Select from the drop-down menus to correctly describe the end behavior of ​ f(x) ​. As x decreases without bound, the graph of f(x) . As x increases without bound, the graph of f(x) . An exponential curve graphed on a coordinate plane with horizontal x-axis ranging from negative 4 to 4 in increments of 1. The vertical y-axis ranges from negative 5 to 5 in increments of 1. The curve begins from the second quadrant. The curve increases through begin ordered pair 0 comma 0.2 end ordered pair. The curve passes through begin ordered pair 1 comma 1 end ordered pair and moves away from the positive y-axis.

Answer 1

Answer: As x decreases without bound the graph f(x) decreases, as x increases without bound the graph of f(x) increases.

Step-by-step explanation:

Since, the given function is , $f(x) =5(x-1)$

If $x\rightarrow -\infty$ then $f(x)\rightarrow -\infty$

that is, we can say, as x decreases without bound the graph f(x) decreases.

While, If $x\rightarrow +\infty$ then $f(x)\rightarrow +\infty$

That is, we can say, as x increases without bound the graph f(x) increases.

thus, we can say first option represents the correct end behavior of f(x).

Answer 2

Answer:

As x decreases without bound the graph f(x) decreases, as x increases without bound the graph of f(x) increases.

explaination step by step:

Since, the given function is , f(x) =5(x-1)f(x)=5(x−1)

If x\rightarrow -\inftyx→−∞ then f(x)\rightarrow -\inftyf(x)→−∞

that is, we can say, as x decreases without bound the graph f(x) decreases.

While, If x\rightarrow +\inftyx→+∞ then f(x)\rightarrow +\inftyf(x)→+∞

That is, we can say, as x increases without bound the graph f(x) increases.

thus, we can say first option represents the correct end behavior of f(x).