Respuesta :
I'll use synthetic division: (you can also use long division or factoring)
6 | 4 -27 18
| 24 -18
__________
4 -3 0
So the quotient is 4x-3
6 | 4 -27 18
| 24 -18
__________
4 -3 0
So the quotient is 4x-3
Answer: The required quotient of the given division is (4x - 3).
Step-by-step explanation: We are given to find the following quotient :
[tex]Q=(4x^2-27x+18)\div(x-6)=\dfrac{4x^2-27x+18}{x-6}~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
To find the given quotient, first we need to factorize the numerator and then we will try to divide it by the denominator.
From (i), we have
[tex]Q\\\\\\=\dfrac{4x^2-27x+18}{x-6}\\\\\\=\dfrac{4x^2-24x-3x+18}{x-6}\\\\\\=\dfrac{4x(x-6)-3(x-6)}{x-6}\\\\\\=\dfrac{(x-6)(4x-3)}{(x-6)}\\\\=4x-3.[/tex]
Thus, the required quotient of the given division is (4x - 3).