Question

−15x+4≤109 OR −6x+70>−2

Answer 1

-15x+4≤109
-15x≤105
x≥-7
x∈[-7;+∞)

-6x+70>-2
-6x>-72
x<12
x∈(-∞; 12)

Answer 2

Answer:

(-∞, ∞)

Step-by-step explanation:

$-15x+4\leq 109$ OR $-6x+70>-2$

Solve each inequality for x

$-15x+4\leq 109$, Subtract 4 from both sides

$-15x\leq 105$, divide the inequality by -15

Reverse the inequality sign when we divide by negative number

$x\geq -7$

$-6x+70>-2$

Subtract 70 from both sides

$-6x>-72$, divide both sides by -6, reverse the inequality sign

$x<12$

WE got $x\geq -7$ or $x<12$

When we graph both inequality , the solution is all real numbers

(-∞, ∞)