Using distance between two points, it is found that the perimeter of the rectangle is of 33.9 units, given by option D.
The perimeter of a rectangle of length l and width w is given by:
[tex]P = 2(l + w)[/tex]
- In this problem, the rectangle is on the cartesian map, which means that these dimensions are found using the formula for the distance between two points.
The distance between two points [tex](x_0, y_0)[/tex] and [tex](x_1,y_1)[/tex] is given by:
[tex]D = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2}[/tex]
The length is the distance between points (3,8) and (6,5), thus:
[tex]l = \sqrt{(6 - 3)^2 + (5 - 8)^2} = \sqrt{18}[/tex]
The width is the distance between points (-3,-4) and (6,5), thus:
[tex]w = \sqrt{(5 - (-4))^2 + (6 - (-3))^2} = \sqrt{162}[/tex]
Then, the perimeter is of:
[tex]P = 2(l + w) = 2(\sqrt{18} + \sqrt{162}) = 33.9[/tex]
The perimeter is of 33.9 units, given by option D.
A similar problem is given at https://brainly.com/question/16642085