Question

WILL MARK BRAINLIEST ANSWER
2x^2+20x=-38
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Answer 1

2x^2+20x = -38

2x^2 + 20x + 38 = 0

Divide both sides by 2.

x^2 + 10x + 19 = 0

The quadratic formula works very well here.

Let a = 1, b = 10 and c = 19

x = [-b +- sqrt{b^2 - 4ac}]/(2a)

Plug those values into the formula to find two answers for x.

One is negative and the other positive.

Good luck.

Answer 2

Move 38 to the left side of the equation by adding it to both sides.
2x ^2 + 20x + 38 = 0
Use the quadratic formula to find the solutions.
−b±√b^2 − 4 (ac)/2a
Substitute a = 2, b = 20, and c = 38 into the quadratic formula and solve for x.
−20±√20 ^2 − 4⋅(2⋅38)/2⋅2
Simplify. x = −5±√6
The result can be shown in both exact and approximate form.
x = −5±√6
x ≈ −2.55051025, −7.44948974