A student has passed 60 percent of the 20 quizzes he has written so far successfully. if the student writes 50 quizzes during the year, and passes 80 percent of the remaining quizzes successfully, what would his average percentile be?answer:

Respuesta :

60% of 20 is (0.6 x 20) = 12 passes There are a further 30 quizzes remaining (50 total during the year minus 20 already written) 80% of 30 is (0.8 x 30) = 24 passes The student has passed (12 + 24) = 36 quizzes out of 50 total, giving an overall pass percentage of ((36 / 50) x 100)) = 72%.

His average percentile is 72%

  • A student passed 60 percent out of 20 quizzes
  • 50 quizzes in a year and passed 80 percent of the remaining quizzes
  • The success rate for all his quizzes for the entire year is unknown.

Further Explanation

A student passed 60 percent out of 20 quizzes, which can be expressed as  

[tex]\frac{60}{100}[/tex] x [tex]20[/tex]

[tex]60[/tex] x [tex]\frac{20}{100}[/tex]

[tex]\frac{1200}{100}[/tex]

[tex]12[/tex]  

Therefore the remaining quizzes will be:

[tex]50[/tex] - [tex]20[/tex]

[tex]30[/tex] quizzes

Also, we have to determine the 80% of 30 quizzes, which can also be expressed as

[tex]\frac{80}{100}[/tex] x [tex]30[/tex]

[tex]80[/tex] x [tex]\frac{30}{100}[/tex]

[tex]\frac{2400}{100}[/tex]

[tex]24[/tex]

To find the total remaining quizzes, then we have to add both value together

Therefore, we have

[tex]30[/tex] + [tex]24[/tex]

[tex]36[/tex]

Thus, the total remaining quizzes is 36.

Now, if the student writes 50 quizzes during the year, his average percentile would be:

[tex]\frac{36}{50}[/tex] x [tex]100%[/tex]

[tex]0.72[/tex] x [tex]100%[/tex]

[tex]72%[/tex]

Therefore, his average percentile is 72%

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KEYWORDS:

  • quizzes
  • students
  • percentage
  • success year  
  • entire year
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