Question

What mass in grams of ethylene oxide is needed to react with 18 g of water?

Answer 1

C2H4O + H2O = C2H6O2 moles water = 18 g/ 18.02 g/mol=.998 the ratio is 1 : 1 : 1 moles C2H4O needed = 0.998 mass C2H4O = 0.998 mol x 44.053 g/mol = 44.00 g We require 44.00 g of ethylene oxide is needed to react with 18 g of water.