Answer:
[tex]2.46x10^{22}atoms[/tex]
Explanation:
Hello,
In this case, we need to compute the atoms of both phosphorous and oxygen, taking into account the following mass-mole-atoms relationship:
[tex]Molar,mass=31*2+16*5=142g/mol\\atomsP=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{2molP}{1molP_2O_5} *\frac{6.022x10^{23}atomsP}{1molP}=7.04x10^{21}atomsP\\atomsO=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{5molO}{1molP_2O_5} *\frac{6.022x10^{23}atomsO}{1molO}=1.76x10^{22}atomsO[/tex]
Now, by adding each result, we've got:
[tex]atoms=1.76x10^{22}atomsP+7.04x10^{21}atomsO=2.46x10^{22}atoms[/tex]
Best regards.
