Question

Water flows over a section of niagara falls at a rate of 6.00 ´ 105 kg/s and falls 50.0 m. what is the power dissipated by the waterfall?

Answer 1

The answer is: PE lost every second = mgh = 1.2x10^6 * 9.81 * 50 = 5.89x10^8J So, Power = 5.89x10^8W