Question

In which function is x = 2 mapped to 32?
A. f(x) = -3x^2-4
B. g(x) = 4(x+3)^2-68
C. h(x) = 3x
D. j(x) = 2x-62

Answer 1

B. Let P(x) be any polynomial, take P(2)
if P(2)=32 then that is ur answer

Answer 2

Answer:

Option B - $g(x) = 4(x+3)^2-68$  

Step-by-step explanation:

Given : Function is x = 2 mapped to 32.

To find : Which function is it ?

Solution : We put x=2 in every function and which result to 32 is the answer.

A. $f(x) = -3x^2-4$

$f(2) = -3(2)^2-4$

$f(2) = -3(4)-4$

$f(2) = -12-4$

$f(2) = -16$

B. $g(x) = 4(x+3)^2-68$

$g(2) = 4(2+3)^2-68$

$g(2) = 4(5)^2-68$

$g(2) = 4(25)-68$

$g(2) = 100-68$

$g(2) = 32$

C. $h(x) = 3x$

$h(2) = 3(2)$

$h(2) = 6$

D. $j(x) = 2x-62$

$j(2) = 2(2)-62$

$j(2) = 4-62$

$j(2) =-58$

Option B -$g(x) = 4(x+3)^2-68$  gave you the result  $g(2) = 32$

Therefore, Option B is correct.