Question

A 10.0 kg block on a table is connected by a string to a 63 kg mass, which is hanging over the edge of the table. assuming that frictional forces may be neglected, what is the magnitude of acceleration of the block when the other block is released?

Answer 1

Answer:

8.45m/s^2

Explanation:

a = m2g / m1+m2

63 + 10 = 73 kg

63*9.8 / 73 = 8.45m/s^2

Answer 2

The magnitude of the acceleration of the block when the other block is released would be 8.466 m/s²

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem A 10.0 kg block on a table is connected by a string to a 63 kg mass, which is hanging over the edge of the table. assuming that frictional forces may be neglected,

The force responsible for the motion is only due to the hanging mass of 63Kg  because of the gravitational pull of the earth

F = mg  

  = 63×9.81 N

  =618 N

the acceleration would be the same for both the block as both are connected by a string

a = F/(m₁+m₂)

a = 618/(63+10)

a = 8.466 m/s²

Thus , The magnitude of the acceleration of the block when the other block is released would be 8.466 m/s²

Learn more about Newton's second law, here

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