The two consecutive integers are: 22, and 23 .
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x + (x + 1) = 45 ;
in which:
"x" is the first integer (of the 2 consecutive integers) ;
"(x + 1)" is the second integer (of the 2 consecutive integers);
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We want to solve for "x";
which is the first integer (of the 2 consecutive integers);
then we can solve for the second integer (of the 2 consecutive integers);
as well;
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We have:
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x + (x + 1) = 45 ;
Rewrite as:
x + x + 1 = 45 ;
↔ 1x + 1x + 1 = 45 ;
→ 2x + 1 = 45 ;
Subtract "1" from each side of the equation;
2x + 1 −1 = 45 − 1 ;
to get:
2x = 44 ;
Divide EACH SIDE of the equation by "2" ; to isolate "x" on one side of the equation; and to solve for "x" ;
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2x / 2 = 44 / 2 ;
to get: x = 22 ;
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Our two consecutive integers:
x = 22 ;
(x + 1) = 22 + 1 = 23 .
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The two consecutive integers are: "22" and "23" .
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Let us check our answer:
Are "22" and "23" consecutive integers? Yes!
Do "22" and "23" add up to "45" ? ;
→ 22 + 23 = ? 45 ? ; Yes!
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