Question

What is the value of work done on an object when a 10–newton force moves it 30 meters and the angle between the force and the displacement is 25°?

Answer 1

The component of force which is parallel to the path of the motion is 10N * cos25 = 9.06 N 
This component is the only "effective" force, and it is the one doing work. 

Work = force * distance

Work = 9.06 N * 30 m

Work = 2.7×10^2 J

Answer 2

Answer:

2.7×10^2 Joules

Explanation: