Respuesta :

the answer to this question is y=28

Answer-

[tex]\boxed{\boxed{y^{\circ}=26^{\circ}\ 45'}}[/tex]

Solution-

As the triangle ABC is an isosceles triangle, with AC = BC.

So the angles A and B will be same, i.e

[tex]\Rightarrow \angle A=\angle B[/tex]

[tex]\Rightarrow 34^{\circ}=(x-5)^{\circ}[/tex]

[tex]\Rightarrow x^{\circ}=34^{\circ}+5^{\circ}[/tex]

[tex]\Rightarrow x^{\circ}=39^{\circ}[/tex]

As sum of all angles in a triangle is 180°, so

[tex]\Rightarrow \angle A+\angle B+\angle C=180^{\circ}[/tex]

[tex]\Rightarrow 34^{\circ}+39^{\circ}+4y^{\circ}=180^{\circ}[/tex]

[tex]\Rightarrow 4y^{\circ}=180^{\circ}-34^{\circ}-39^{\circ}[/tex]

[tex]\Rightarrow 4y^{\circ}=107^{\circ}[/tex]

[tex]\Rightarrow y^{\circ}=\dfrac{107^{\circ}}{4}[/tex]

[tex]\Rightarrow y^{\circ}=26.75^{\circ}[/tex]

[tex]\Rightarrow y^{\circ}=26^{\circ}\ 45'[/tex]

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