Simplify the expression x^2+3x-28/x^2-7x+12

Answer:
[tex]\frac{x+7}{x-3}[/tex].
Step-by-step explanation:
We have been given an expression. We are asked to simplify our given expression.
[tex]\frac{x^2+3x-28}{x^2-7x+12}[/tex]
Let us factor numerator and denominator by splitting the middle term.
[tex]\frac{x^2+7x-4x-28}{x^2-4x-3x+12}[/tex]
[tex]\frac{(x^2+7x)+(-4x-28)}{(x^2-4x)+(-3x+12)}[/tex]
Factor out GCF of each group:
[tex]\frac{x(x+7)-4(x+7)}{x(x-4)-3(x-4)}[/tex]
[tex]\frac{(x+7)(x-4)}{(x-4)(x-3)}[/tex]
Cancel out common factor [tex](x-4)[/tex]:
[tex]\frac{(x+7)}{(x-3)}[/tex]
Therefore, the simplified form of the given expression would be [tex]\frac{x+7}{x-3}[/tex].