Respuesta :

X^2 + 3x - 28 factors to (X+7)(X-4)
X^2  - 7X + 12 factors to (X-4)(X-3)
Now we see that the equation is [(X+7)(X-4)]/[(X-4)(X-3)]
By dividing the top and bottom by (X-4), we see that the equation equals (X+7)/(X-3).

Answer:

[tex]\frac{x+7}{x-3}[/tex].

Step-by-step explanation:

We have been given an expression. We are asked to simplify our given expression.

[tex]\frac{x^2+3x-28}{x^2-7x+12}[/tex]

Let us factor numerator and denominator by splitting the middle term.

[tex]\frac{x^2+7x-4x-28}{x^2-4x-3x+12}[/tex]

[tex]\frac{(x^2+7x)+(-4x-28)}{(x^2-4x)+(-3x+12)}[/tex]  

Factor out GCF of each group:

[tex]\frac{x(x+7)-4(x+7)}{x(x-4)-3(x-4)}[/tex]

[tex]\frac{(x+7)(x-4)}{(x-4)(x-3)}[/tex]

Cancel out common factor [tex](x-4)[/tex]:

[tex]\frac{(x+7)}{(x-3)}[/tex]

Therefore, the simplified form of the given expression would be [tex]\frac{x+7}{x-3}[/tex].

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