Answer:
1.16 in
2.24 in
3.12.8 in
Step-by-step explanation:
We are given that
Width of photo=5 in
Length of photo=8 in
We have to find the length of new photo in each case.
1. Let x represent the width and y represents the length of photo.
When width increase then length of photo is also increases then it is direct proportion.
[tex]\frac{x_1}{y_1}=\frac{x_2}{y_2}[/tex]
Substitute the values then we get
[tex]\frac{5}{8}=\frac{10}{y}[/tex]
[tex]y=\frac{10\times 8}{5}=16[/tex]
Hence, the length of photo=16 in
2.Width=x=15 in
Again using the formula
[tex]\frac{5}{8}=\frac{15}{y}[/tex]
[tex]y=\frac{15\times 8}{5}=24[/tex]
Hence, the length of new photo=24 in
3. Width =x=8 in
Substitute the values in the given formula
[tex]\frac{5}{8}=\frac{8}{y}[/tex]
[tex]y=\frac{8\times 8}{5}=\frac{64}{5}=12.8[/tex]
Hence, the length of new photo=12.8 in
