Respuesta :

z = sin(2xy)   Ill use D for the partial differential sign

Dz/Dx =  2ycos(2xy)
Dz/Dy =  2xcos(2xy)

D^2z/Dx^2 = 2y.-2ysin(2xy)  = - 4y^2sin(2xy)
D^2z/Dy^2 =  -4x^2sin(2xy)

D^2z/Dy.Dx =  D/Dy( Dz/Dx) =  2y. -2xsin(2xy) + 2.cos(2xy) 

 =  -4xysin(2xy)  + 2 cos(2xy)

D^2z(Dx.Dy)  is the same as the latter.
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