Respuesta :
Answer:
All the numbers are less than and equal to 18.
Step-by-step explanation:
To find : All numbers such that a third of a number increased by half that number is at least 3 less than that same number ?
Solution :
Let the number be 'x',
A third of a number is [tex]\frac{x}{3}[/tex]
Half that number is [tex]\frac{x}{2}[/tex]
3 less than that same number is [tex]x-3[/tex]
A third of a number increased by half that number is at least 3 less than that same number is written as,
[tex]\frac{x}{3}+\frac{x}{2}\geq x-3[/tex]
[tex]\frac{2x+3x}{6}\geq x-3[/tex]
[tex]\frac{5x}{6}\geq x-3[/tex]
[tex]5x\geq 6x-18[/tex]
[tex]5x-6x\geq -18[/tex]
[tex]-x\geq -18[/tex]
[tex]x\leq 18[/tex]
Therefore, all the numbers are less than and equal to 18.
The set of numbers such that a third of a number increased by half that number is at least 3 less than that same number are given as; x <= 18.
According to the question;
Let the numbers in question be represented as x.
In essence;
[tex] \frac{x}{3} + \frac{x}{2 } \geqslant x - 3[/tex]
[tex] \frac{5x}{6} \geqslant x - 3[/tex]
- 5x >= 6x - 18
- -x >= -18
- x <= 18
Therefore, the set of numbers such that a third of a number increased by half that number is at least 3 less than that same number are given as; x <= 18.
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