Respuesta :

Answer:

All the numbers are less than and equal to 18.

Step-by-step explanation:

To find : All numbers such that a third of a number increased by half that number is at least 3 less than that same number ?

Solution :

Let the number be 'x',

A third of a number is [tex]\frac{x}{3}[/tex]

Half that number is [tex]\frac{x}{2}[/tex]

3 less than that same number is [tex]x-3[/tex]

A third of a number increased by half that number is at least 3 less than that same number is written as,

[tex]\frac{x}{3}+\frac{x}{2}\geq x-3[/tex]

[tex]\frac{2x+3x}{6}\geq x-3[/tex]

[tex]\frac{5x}{6}\geq x-3[/tex]

[tex]5x\geq 6x-18[/tex]

[tex]5x-6x\geq -18[/tex]

[tex]-x\geq -18[/tex]

[tex]x\leq 18[/tex]

Therefore, all the numbers are less than and equal to 18.

The set of numbers such that a third of a number increased by half that number is at least 3 less than that same number are given as; x <= 18.

According to the question;

Let the numbers in question be represented as x.

In essence;

[tex] \frac{x}{3} + \frac{x}{2 } \geqslant x - 3[/tex]

[tex] \frac{5x}{6} \geqslant x - 3[/tex]

  • 5x >= 6x - 18

  • -x >= -18

  • x <= 18

Therefore, the set of numbers such that a third of a number increased by half that number is at least 3 less than that same number are given as; x <= 18.

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