Question

Which ordered pair is the solution to the system of equations? {−3x+4y=−20{,y=x−4 A.(−4, −8) .B.(−2, −6) C.(4, 8) D.(0, −5)

Answer 1

-3x + 4y = -20
y = x - 4

Put the second equation into the first equation in place of y.

-3x + 4 (x - 4) = -20

Multiply everything in the parenthesis by 4.

-3x + 4x - 16 = -20

Combine like terms.

x - 16 = -20

Add 16 to both sides.

x = -4

Put this into the second equation in place of x.

y = -4 - 4

y = -8

Your solution set is (-4,-8).

Hope this helps!

Answer 2

The solution of the given system of equations is (-4, -8).

Therefore, option A is correct.

Given equations are,

                          $-3x+4y=-20..........(1)\\\\y=x-4 .........(2)$

Substituting the value of equation 2 in equation 1.

                   $-3x+4(x-4)=-20\\\\-3x+4x-16=-20\\\\x=-20+16=-4$

Substituting the value of x in equation 2

We get,      $y=-4-4=-8$

The solution is (-4, -8)

Therefore, option A is correct.

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