A male is heterozygous for the trait that produces freckles on the skin, and he has freckles. if he marries a woman who is also heterozygous for freckles, ______ percent of their children are predicted to be freckled. also, of all their children, ______ percent are predicted to be heterozygous.

Respuesta :

underV
F- allele for freckles
f-
allele without freckles

1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also
heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 -
heterozygote with freckles: Ff
- 1/4-
homozygote without freckles:ff

Their son would have a probability of 75% of being born with freckles.


2) The cross resulted in this probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 -
heterozygote with freckles: Ff
- 1/4-
homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
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