The solution to the system of equations are (1, 3) and (-5, -3)
Given the following functions
Y=x^2+5x-3
Y-x=2; y = x + 2
Equating both outputs will give
x^2+5x-3 = x + 2
x^2+5x-3 - x - 2 = 0
x^2 + 4x - 5 = 0
Factorize the equation
x^2 + 5x - x - 5=0
x(x+5) - 1(x+5) = 0
(x-1)(x+5) = 0
x = 1 and -5
Recall that y = x + 2
y = 3 and -3
Hence the solution to the system of equations are (1, 3) and (-5, -3)
Learn more here: https://brainly.com/question/20360246
