Question

Solve 11sinθ-2=2 for a value of θ when 0≤θ≤π/2.? How do you solve the second problem?

Answer 1

5cos (2x)+7=cos (2x)+8, 4cos (2x)=1, cos (2x)=1/4, 2x=arccos(1/4), x=(1/2)arccos (1/4). I used x instead of theta, and arccos is cos inverse