Respuesta :
1.) You plug a number into the variable x. Then you will solve the equation for h(x) to find the time it takes for the rocket to travel the path given.
Answer:
Step-by-step explanation:
Given that a rocket path is given by
[tex]h(x) = -4x^2 + 16x[/tex]
When it hits the ground h(x) =0
Hence we get
[tex]-4x^2 + 16x=0\\x=0, 4[/tex]
i.e. after 4 minutes the rocket hits the ground
2) Given that
[tex]s(t) = -16t^2 + 48t + 280.[/tex]
We have to find time t when height >280
[tex]s(t) = -16t^2 + 48t + 280>280\\\\t=0, 3[/tex]
Between 0 and 3 seconds the object would be above the building.