The ratio of the amount of money Jason had to the amount of money Wilson had was 12:13, then Jason had $12x and Wilson had $13x.
Wilson spent $63, then in the end he had $(13x-63). Since in the end Jason had 3 times as much money as Wilson, then
[tex]\dfrac{12x}{13x-63}=3.[/tex]
Solve it:
[tex]12x=3(13x-63),\\ \\12x=39x-189,\\ \\27x=189,\\ \\x=7.[/tex]
In the beginning Jason had $12·7=$84 and Wilson had $13·7=$91. In the end Jason had $84 and Wilson had $91-$63=$28.
Answer: Jason had $84, in the end altogether they had $84+$28=$112.
