Question

1. Perform a cross between two pea plants with the following characteristics: One is heterozygous for the dominant trait of wrinkled seeds (W); the other is homozygous for the recessive trait of smooth seeds (w). Fill in the genotypes of the offspring in the Punnett square. Then state the percentages of each genotype and phenotype of the offspring.

Answer 1

Ww, Ww, ww, ww

 0% homozygous dominant (WW), 50% heterozygous (Ww) and 50% homozygous recessive (ww). The phenotype is 50-50, or half wrinkled seeds, half smooth seeds (2 Ww : 2 ww) 

Answer 2

Answer:

Possible Genotypes are Ww and ww

Percentage of genotype Ww - $50$%

Percentage of genotype ww - $50$%

Possible phenotypes are Wrinkled and smooth

Percentage of Wrinkled  phenotype  - $50$%

Percentage of smooth phenotype - $50$%

Explanation:

Given -

Parent I  is heterozygous for the dominant trait of wrinkled seeds. Thus, its genotype would be "Ww"

Parent II is homozygous for the recessive trait of smooth seeds. Thus, its genotype would be "ww"

The punnet square representing the cross between "Ww" and "ww" is as follows -

W w

w Ww ww

w Ww ww

Possible Genotypes are Ww and ww

Percentage of genotype Ww - $50$%

Percentage of genotype ww - $50$%

Possible phenotypes are Wrinkled and smooth

Percentage of Wrinkled  phenotype  - $50$%

Percentage of smooth phenotype - $50$%