Question

What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x4+5 ? Enter your answer in the box.

Answer 1

y = x/4 + 5, slope = 1/4

perpendicular lines, slope is opposite and reciprocal
so slope = -4

passes through the point (2, 7)
y = mx + b
b = y - mx
b = 7 - (-4)(2)
b = 7 + 8
b = 15

equation
y = -4x + 15

answer
y = -4x + 15