Step 1
Find the slope of the given line
we have
[tex]3x+4y=15[/tex]
Isolate the variable y
Subtract [tex]3x[/tex] both sides
[tex]3x+4y-3x=15-3x[/tex]
[tex]4y=-3x+15[/tex]
Divide by [tex]4[/tex] both sides
[tex]y=-\frac{3}{4}x+ \frac{15}{4}[/tex]
the slope of the given line is
[tex]m=-\frac{3}{4}[/tex]
Step 2
Find the equation of the line that passes through the point [tex](8,-2)[/tex] and is parallel to the given line
we know that
if two lines are parallel, then their slopes are equal
The equation of the line into point-slope form is equal to
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]m=-\frac{3}{4}[/tex]
[tex](x1,y1)=(8,-2)[/tex]
substitute in the equation
[tex]y+2=-\frac{3}{4}(x-8)[/tex]
[tex]y=-\frac{3}{4}x+6-2[/tex]
[tex]y=-\frac{3}{4}x+4[/tex] or [tex]3x+4y=16[/tex]
therefore
the answer is
[tex]y=-\frac{3}{4}x+4[/tex]
or
[tex]3x+4y=16[/tex]
