The expected value of events [tex]x_i[/tex] with probabilities [tex]p(x_i)[/tex] is given by
[tex]E(x)=\Sigma x_ip(x_i)[/tex]
Given that in a game, Sam wins $1 with the probability of [tex]\frac{1}{3}[/tex] , $5 with the probability of [tex]\frac{1}{6}[/tex] , and $0 with the probability of [tex]\frac{1}{2}[/tex]
Sam's expected winnings is given by:
[tex]E(x)=1\left( \frac{1}{3} \right)+5\left( \frac{1}{6} \right)+0\left( \frac{1}{2} \right) \\ \\ =\frac{1}{3}+\frac{5}{6}= \frac{7}{6} =1.17[/tex]
Therefore, Sam's expected winnings is $1.17