Respuesta :

[tex]y=2x^2\implies\mathbf r(x)=\langle x,2x^2\rangle[/tex]

[tex]\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=\int_{t=-1}^{t=1}\langle-2x^2,x^2\rangle\cdot\langle1,4x\rangle\,\mathrm dx[/tex]
[tex]=\displaystyle\int_{-1}^1(8x^3-2x^2)\,\mathrm dx[/tex]
[tex]=-\dfrac43[/tex]
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