Question

A 0.300 kg ball is thrown vertically upward with an initial speed of 17.0 m/s . part a what is the maximum height reached by the ball?

Answer 1

1/2 mv^2 = mgh, all of the initial kinetic energy is converted to potential energy

So (since you can see how 'm' divides out):
(0.5)v^2 = gh, g= acceleration of gravity
(0.5)(20.0)^2 = (9.8)h
200 = 9.8h
h=20.4 m