A car traveling at 40.4 m/s skids to a stop in 3.34 s. Determine the skidding distance of the car. (Assume uniform acceleration ) Be sure to show your work.
Okay so you have to find acceleration first. I used v=vo+at. Plug in the numbers and you get -11.9m/s^2 as your constant acceleration. Then plug acceleration into d=vi(t)+1/2(a)t^2 d=(40m/s)(3.34s)+1/2(-11.9m/s^2)(3.34s)^2 d=68.6m
