Question

Find 3 consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91?

Answer 1

suppose the smallest odd integer is n, the next one is then n+2, and the third one is n+4
7n+2(n+4)=-91
7n+2n+8=-91
9n=-99
n=-11
so the three odd integers are -11,-9,-7