Let Opp Adj, and Hypp respectively represent the opposite side, the adjacent side, and the hypotenuse.
Consider an angle M with measure m degrees. The trigonometric ratios sec, and csc are defined as follows:
sec(m)=Hyp/Adj, and csc(m)=Hyp/Opp
Thus we can check that
[tex]\displaystyle{csc(\angle C)= \frac{6}{4}= \frac{3}{2} [/tex]
[tex]\displaystyle{sec(\angle C)= \frac{6}{5} [/tex]
[tex]\displaystyle{csc(\angle B)= \frac{6}{5}= \frac{3}{2} [/tex]
[tex]\displaystyle{sec(\angle C)= \frac{6}{4}=\frac{3}{2} [/tex]
Answer: A