The last step is to calculate the percent by mass of each element in ammonium nitrate (NH4NO3). The masses of the elements in one mole of the compound are: mass N = 28.0 g mass H = 4.0 g mass O = 48.0 g The molar mass of the compound is 80.0 g/mol. What is the mass of one mole of the compound? 80.0g
Answer: 80 g
Explanation:Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.
Mass of 1 mole of compound=mass of nitrogen + mass of hydrogen+ mass of oxygen= 28+4+48 = 80 g.
Percentage by mass of nitrogen=[tex]\frac{\text {mass of nitrogen}}{\text {Total mass}}\times 100\ %[/tex]
Percentage by mass of nitrogen=[tex]\frac{28}{80}\times 100\%=35\%[/tex]
Percentage by mass of hydrogen=[tex]\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\%[/tex]
Percentage by mass of hydrogen=[tex]\frac{4}{80}\times 100\%=5\%[/tex]
Percentage by mass of oxygen=[tex]\frac{\text {mass of oxygen}}{\text {Total mass}}\times 100\%[/tex]
Percentage by mass of oxygen=[tex]\frac{48}{80}\times 100\%=60\%[/tex]
