Question

Given right triangle def what is the value of sin e

Answer 1

right triangle
10^2 - 8^2 = 100 - 64 = 36
DF = √36
DF = 6
so
sinE = Opp / Hypo
sinE = 6/10
sinE = 3/5

Answer 2

Answer:

Step-by-step explanation:

From the given triangle DEF, we have

$(EF)^{2}=(ED)^{2}+(DF)^{2}$

$(10)^{2}=(8)^{2}+(DF)^{2}$

$100-64=(DF)^2$

$DF=6$

Now, we know that SinE=$\frac{Perpendicular}{Hypotenuse}$, thus

$SinE=\frac{DF}{EF}$

$SinE=\frac{6}{10}=\frac{3}{5}$

Therefore, the value of SinE is $\frac{3}{5}$.