Question

19 ) 23a ³b ² / 69ab ³

pakai cara ya guys

Answer 1

$\frac{23a^3b^2}{69ab^3}$

You simplify out...69 and 23 (divide each for 3), a^3 and a (since you divide them, you have to subtract the exponents...3-1 = 2), b^2 and b^3 (3-2 = 1)

$\frac{a^2}{3b}$ (final result)

So a²/3b