Question

the average marks of shahid first four papers is 88 how much mark should he get in the fifth paper so that the average of five papers becom 90?
a.92
b.94
c.96
d.98

Answer 1

your answer is D. 98
88*4=352
90*5=450
hence 450-352=98

Answer 2

Answer with Step-by-step explanation:

The average marks of Shahid first four papers is 88.

Let a,b,c and d be the marks in first four papers

⇒  $\dfrac{a+b+c+d}{4}=88$

⇒  a+b+c+d=88×4

                  =352

Let marks in fifth paper be x

The average of five papers become 90

⇒ $\dfrac{a+b+c+d+x}{5}=90$

⇒ a+b+c+d+x=90×5

⇒  352+x=450   (since a+b+c+d=352)

⇒ x=450-352

⇒ x=98

Hence, Correct option is:

d.98