Question

If the speed of the skateboarder at point a is v=1.8m/s, what is her speed at point b? assume that friction is negligible.

Answer 1

Here,let the speed at B is vfUsing conservation of energy0.5 * m * (vf^2 - v^2) = m * g * (2.7 -1)0.5 * (vf^2 -1.8^2) = 9.8 * (1.7)solving for vfvf = 6.05 m/sthe speed at B is  6.05 m/s