Question

One car rental company charges $30 per day plus $0.25 per mile driven. a car company charges $40 per day plus $0.10 per mile driven. how many miles must you drive for a one-day rental at the second company to be less expensive than the same rental at the first company? write an inequality to solve.

Answer 1

Rewrite the question into equations:
let's say x is the miles you drive for a day
the first company's rental charge= $30+$0.25x
the second company's rental charge= $40+$0.10x

Calculate what the x is when two equations are equal to each other:
$30+$0.25x=$40+$0.10x
$0.25x-$0.10x=$40-$30
$0.15x=$10
x=$10/$0.15
x=66.667 miles

at least 66.667 miles. I am not sure though. I'm a little bit tired today, so you might want to check it yourself.

Answer 2

Answer:

66.667 miles

Step-by-step explanation:

Given: One car rental company charges $30 per day plus $0.25 per mile driven.

Second car company charges $40 per day plus $0.10 per mile driven.

To find:  how many miles must you drive for a one-day rental at the second company to be less expensive than the same rental at the first company?

Solution: Let the distance driven on a day be x miles.

As per question,

The first rental company will charge $=30+0.25x$

The second rental company will charge $=40+0.10x$

Now, we want the rental charges of second company to be less expensive then the first.

So we get the inequality,

$30+0.25x>40+0.10x$

$0.25x-0.10x>40-30$

$0.15x>10$

$x>\frac{1000}{15}$

$x>66.667$ miles

Hence, at least 66.667 miles should be driven on a day.