Question

how do you put (x+5)(x-3)[x-(4-i)][x-(4+i)] into standard form

Answer 1

$(x+5)(x-3)[x-(4-i)][x-(4+i)] \\ (x^{2}+5x-3x-15)(x-4+i)(x-4-i) \\ (x^{2}+5x-3x-15)(x^{2} -4x-xi-4x+16+4i+xi-4i- i^{2} ) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16- i^{2}) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16-(-1)) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16+1) \\ (x^{2}+5x-3x-15)( x^{2} -8x+17)$ 
From there just distribute and simplify.