Question

40 POINTS!!!!! A submarine descends to 1/6 of its maximum depth. Then it descends another 2/3 of its maximum depth. If it is now at 650 feet below sea level, what is its maximum depth? Show your work.

Answer 1

Answer:

The maximum is 780.

Step-by-step explanation:

1/6x+2/3x=650

Which is: 1/6x+4/6x=650

5/6x=650

5/6x÷5/6=650÷5/6

x=650 × 6/5

x= 780

Answer 2

The maximum depth the submarine descends to is; 780 ft

• Let the maximum depth be x.

It descends to 1/6 of max depth = (1/6)x

It descends another 2/3 of max depth = (2/3)x

• After descending the depths above, it is now 650 ft below sea level. Thus;

(1/6)x + (2/3)x = 650

x(1/6 + ⅔) = 650

x(5/6) = 650

x = 6 × 650/5

x = 780 ft

• In conclusion, the maximum depth is 780 ft.

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