A: 9.4248 m
B: 2.773 s
A ball tossed in to the air at 13.6m/s will experience a constant acceleration due to gravity of 9.81m/s^2. It will reach a 0 velocity at
13.6m/s^2 / 9.81m/s^2 = 1.386 s
from the time it was thrown. It will fall to the ground another 1.386 seconds giving a total time in the air of
2*13.6m/s^2 / 9.81m/s^2 = 2.773 s
To calculate the maximum height of the ball we use the fact that acceleration is constant. Between being thrown and reaching the maximum height the velocity constantly accelerates from 13.6m/s to 0 which gives an average velocity of 13.6m/s / 2 = 6.8m/s
Now that we know average velocity and the time, the distance can be calculated.
1.386s * 6.8m/s = 9.4248m
