Question

a woman driving at a speed of 23 m/s sees a deer on the road ahead and applies the brakes when she is 210 m from the deer. If the deer does not move and the car stops right before it hits the deer, what is the acceleration provided by the car's brakes?

Answer 1

velocity initial = 23 m/s
velocity final= 0m/s (car comes to a stop)
distance = 210 m
a=?

plug it in

0 = (23)^2 + 2(a)(210)

-529=420a

a= -1.26 meters per seconds squared

Answer 2

The acceleration provided by the car's brakes is -1.259 $m/s^2$.

Given the following data:

• Initial speed = 23 m/s.

• Distance = 210 meters.

• Final speed = 0 m/s (since the car comes to a stop).

To find the acceleration provided by the car's brakes, we would use the third equation of motion:

$V^2 = U^2 + 2aS$

Where:

• V represents the final speed.

• U is the initial speed.

• a represents the acceleration.

• S is the distance covered.

Substituting the parameters into the formula, we have;

$0^2 = 23^2 + 2a(210)\\\\-529 = 420a\\\\a = \frac{-529}{420}$

Acceleration, a = -1.259 $m/s^2$

Therefore, the acceleration provided by the car's brakes is -1.259 $m/s^2$.

Read more: https://brainly.com/question/8898885