Respuesta :
y = 2x^2 - 4x + 2
y = 2(x^2 - 2x + 1)
2(x - 1)^2 = = 0
so the graph will just touch the x axis at x = 1
So there is one zero duplicity 2.
y = 2(x^2 - 2x + 1)
2(x - 1)^2 = = 0
so the graph will just touch the x axis at x = 1
So there is one zero duplicity 2.
Answer:
The graph has:
One zero with multiplicity 2.
Step-by-step explanation:
We are given a quadratic function in terms of the variable x as:
[tex]y=2x^2-4x+2[/tex]
The number of zeros of this function is equal to the number of points where the graph of this quadratic function intersects the x axis and the corresponding value of x is the root of this quadratic equation.
Hence, after plotting the graph of this quadratic function we observe that the graph meets the x-axis at just one point.
Hence, the number of zeros of the graph is:
One.
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